McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
1. Trigonometric Functions in Right Triangles
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Exercise 61 Page 798

To find the length and the width of the rectangle, write two equations with the given information. Then, to find the diagonal use the Pythagorean Theorem.

G

Practice makes perfect

We are given the ratio of the length and the width of a rectangle as 5:12. Also, the area of the rectangle is 240 square centimeters. Let l and w be the length and the width of the rectangle, respectively.

Ratio of the Length and the Width l/w=5/12
Area of the Rectangle l( w)=240

We want to find the length of the diagonal of the rectangle in centimeters. To do so we will first find the values of l and w. Let's write the two equations as a system of equations. Then we will solve the system by the Substitution Method.

lw= 512 & (I) l(w)=240 & (II)
l= 5w12 l(w)=240
l= 5w12 5w12(w)=240
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(II): Solve for l and w
l= 5w12 5w(w)=2880
l= 5w12 5w^2=2880
l= 5w12 w^2=576
l= 5w12 w^2=24^2
l= 5w12 w=24
l= 5( 24)12 w=24
l=5(2) w=24
l=10 w=24

Now we will find the diagonal. Let's draw a rectangle whose length is 10 and width is 24, and add one of the diagonals of the rectangle.

Since a rectangle has four right angles, we will use the Pythagorean Theorem to find the diagonal d.

d^2=24^2+10^2
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Solve for d
d^2=576+100
d^2=676
d^2=26^2
d=26

We found the diagonal as 26. Therefore, the correct option is G.