McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
5. Law of Cosines
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Exercise 29 Page 827

Practice makes perfect
a

We are told that a triangular picnic area is 11 yards by 14 yards by 10 yards. First, we want to sketch a drawing to represent this picnic area. Let's plot a triangle with side lengths of 11, 14 and 10.

Note that since we do not know anything specific about the triangle, there is more than one correct way to draw it.

b

Let's now think about how we can find the area of the triangular picnic area. Start by recalling the formula for the area of the triangle using sine.

Area=1/2 b csin ATo use this formula, we need to know two side lengths of a triangle and the measure of their included angle. Consider our diagram.

We are given all three side lengths of this triangle. Two find the measure of any angle we can use the Law of Cosines. For simplicity we will choose ∠ A, because it is the largest angle.

Therefore, to find the area of a triangular picnic area we can find the measure of the largest angle using the Law of Cosines. Then we can use this measure and the side lengths of the two sides between which the angle is included in the formula for the area of a triangle using sine.

c

Now, we will find the area of a triangular picnic area. Start by using the Law of Cosines to find the measure of the angle ∠ A. Let's substitute a= 14, b= 11, and c= 10 to isolate cos A.

a^2=b^2+c^2 -2 b c cos A
14^2= 11^2+ 10^2 -2 ( 11)( 10) cos A
â–¼
Solve for cos A
196=121+100-2(11)(10)cos A
196=121+100-220cos A
196=221-220cos A
-25=- 220cos A
-25/-220=cos A
25/220=cos A
0.113636...=cos A
cos A=0.113636...
cos A ≈ 0.114
Now, we can use the inverse cosine ratio and a calculator to find m ∠ A.

m ∠ A = cos ^(-1) 0.114
m ∠ A ≈ 83.454050...
m ∠ A ≈ 83

Knowing the measure of angle ∠ A, we can use the formula for the area of a triangle using sine. We have that b= 11, c= 10, and m∠ A= 83^(∘).

Area=1/2bcsin A
Area=1/2( 11)( 10)sin 83^(∘)
â–¼
Evaluate right-hand side
Area=1/2110sin 83^(∘)
Area=110/2sin 83^(∘)
Area=55sin 83^(∘)
Area=55(0.992546...)
Area=54.59003...
Area≈ 54.6

The area of the triangular picnic area is approximately 54.6 square yards.