McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
5. Law of Cosines
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Exercise 28 Page 827

Practice makes perfect
a

We are given a diagram showing how two bumper cars at an amusement park collide.

We want to find how far apart the cars were before they collided. Therefore, we need to find the value of d. Let's use the Law of Cosines to do so.

For our triangle, the known side lengths are 5.5 and 7, the included angle measure is 118^(∘), and the missing side length is d. Let's substitute these values into the Law of Cosines and find the value of d.

b^2=a^2+c^2-2accos B
d^2=( 5.5)^2+ 7^2-2( 5.5)( 7)cos 118^(∘)
â–¼
Evaluate right-hand side
d^2=30.25+49-2(5.5)(7)cos 118^(∘)
d^2=30.25+49-77cos 118^(∘)
d^2=115.399310...
â–¼
Solve for x
d=sqrt(115.399310...)
d=10.742407...
d≈ 10.7

Note that since a negative side length does not make sense, we only need to consider positive solutions. The two bumper cars were about 10.7 feet apart before they collided.

b

We are told that before the collision a third car was 10 feet from the blue car and 13 feet from the orange car. Let's illustrate this on our diagram. We will mark the third car with red and also name each car with a letter.

We want to find the measures of the angles formed by the three cars before the collision. We will find these angle measures one at a time.

Finding m∠ B

Let's start with finding the measure of the angle ∠ B. To do so, we can use the Law of Cosines. b^2= a^2+ c^2-2 a ccos B Let's substitute a= 13, b= 10.7, and c= 10 to isolate cos B.

b^2=a^2+c^2 -2 a c cos B
( 10.7)^2= 13^2+ 10^2 -2 ( 13)( 10) cos B
â–¼
Solve for cos B
114.49=169+100-2(13)(10)cos B
114.49=169+100-260cos B
114.49=269-260cos B
- 154.51=- 260 cos B
- 154.51/- 260=cos B
154.51/260=cos B
0.594269...=cos B
cos B=0.594269...
cos B ≈ 0.59

Now, we can use the inverse cosine ratio and a calculator to find m ∠ B.

m ∠ B = cos ^(-1) 0.59
m ∠ B ≈ 53.842991...
m ∠ B ≈ 54

Finding m∠ C

Now that we know the measure of ∠ B, we can find m ∠ C using the Law of Sines.

Let's substitute b= 10.7, c= 10, and m ∠ B ≈ 54 to isolate sin C.

sin B/b =sin C/c
sin 54/10.7 = sin C/10
â–¼
Solve for sin C
10 sin 54/10.7 = sin C
sin C = 10 sin 54/10.7

Now we can use the inverse sine ratio to find m ∠ C.

m ∠ C = sin ^(-1) 10 sin 54/10.7
m ∠ C ≈ 49.120703...
m ∠ C ≈ 49

Finding m∠ A

Finally, to find m ∠ A we can use the Triangle Angle Sum Theorem. This tells us that the measures of the angles in a triangle add up to 180. m ∠ A+ 54+ 49 = 180 ⇔ m ∠ A ≈ 77 Finally, we have that the angles between the three cars before the collision were 54^(∘), 49^(∘) and 77^(∘).