McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
7. Congruent and Similar Figures
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Exercise 12 Page P21

Draw a diagram. Think of similar triangles.

65 feet

Practice makes perfect

We want to measure the height of a building based on the shadows and known height in the problem. Let's draw a diagram illustrating the telephone pole, the building, and the shadows.

  • Segment PR illustrates the telephone pole, and PQ is its shadow.
  • Segment BD illustrates the building, and BC is its shadow.

We are asked to find the height of the building, which is BD on our diagram.

The sun is very far away, so the rays that form the shadows of the telephone pole and building are parallel. RQ∥ DC Since both the telephone pole and the building stand on horizontal ground, and both the pole and the building stand vertically, the triangles are similar. △ PQR~ △ BCD In similar triangles, the length of corresponding sides are proportional. DB/RP=BC/PQ If we substitute the measures given on the diagram into this ratio, we can solve the resulting equation for the height of the tree.
DB/RP=BC/PQ
DB/25=52/20
Solve for DB
DB=52/20* 25
DB=65
The height of the building is 65 feet.