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Make a table for the factors of - 6.
Use the factors you find in Part A.
Find the factor for each row and column.
Describe what you have done in each step.
- 2 and 3
Box:
Box:
Factors: (x+3)(x-2)
See solution.
Let's start by writing the factors of - 6, and calculate their sum.
| Factors | Sum of Factors |
|---|---|
| 1 and - 6 | - 5 |
| - 1 and 6 | 5 |
| 2 and - 3 | - 1 |
| - 2 and 3 | 1 |
We see that - 2 and 3 have a product of - 6 and a sum of 1.
We will now write each factor in an empty square. We will also include the positive or negative sign and variable.
For this part, we will find the factor for each row and column of the box.
The factors of x^2+x-6 are (x+3) and (x-2). x^2+x-6 = (x+3)(x-2)
When we use the box method to factor x^2-3x-40, we need to follow four steps.
Now, we will determine the factor pair with a product of - 40 and a sum of - 3. l - 40 ↙ ↘ - 8 + 5 l = - 3 Next, we will place the variable and the factors with their signs in the box.
Finally, we find the factor for each row and column.
The factors of x^2-3x-40 are (x+5) and (x-8). x^2-3x-40 = (x+5)(x-8)