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McGraw Hill Glencoe Algebra 1, 2012

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McGraw Hill Glencoe Algebra 1, 2012 View details

2. Multiplying a Polynomial by a Monomial

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Exercise 12 Page 474

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

c=2

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left- and right-hand sides of the equation.

- 6(11-2c)=7(- 2-2c)

Distribute - 6

- 66+12c=7(- 2-2c)

Distribute 7

- 66+12c=- 14-14c

Now we can continue to solve using the Properties of Equality.

- 66+12c=- 14-14c

LHS+14c=RHS+14c

- 66+26c=- 14

LHS+66=RHS+66

26c=52

.LHS /26.=.RHS /26.

c=2

The solution to the equation is c=2. We can check our solution by substituting it into the original equation.

- 6(11-2c)=7(- 2-2c)

c= 2

- 6(11-2( 2)) ? = 7(- 2-2( 2))

▼

Simplify

Multiply

- 6(11-4) ? = 7(- 2-4)

Subtract terms

- 6(7) ? = 7(- 6)

Multiply

- 42 = - 42 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Check Your Understanding p.474

H.O.T. Problems p.476

Standardized Test Practice p.477

Spiral Review p.477

Skills Review p.477