Water is not liquid either when it is frozen or it vaporized. From the given data, we know that water is not liquid for temperatures less than 32^(∘)F or greater than 212^(∘)F. We do not include 32^(∘) F and 212^(∘) F. At these temperatures water starts to change its physicall state and we cannot say if it is a liquid or not.This gives us the following inequality.
We already have the inequalities. The first one is telling us that we should take the values less than 32. Since the inequality sign is strict, we do not include 32 itself.
From the second inequality we have to mark all the points to the right of 212. Again, the inequality sign is strict, so we do not include 212.
The word or means that the final graph is the union of the two solution sets, and combining them we get the following graph.
Mean=212+32/2 ⇒ 244/2=122Now, lets find the distance from midpoint to 32.
Distance=122-32 ⇒ 90
The last piece of information means that we need the points that are further away from the midpoint than the calculated distance, which gives us the following expression.
|t-122|>90
