McGraw Hill Glencoe Algebra 1, 2012
MH
McGraw Hill Glencoe Algebra 1, 2012 View details
5. Inequalities Involving Absolute Value
Continue to next subchapter

Exercise 24 Page 314

Rewrite this inequality as a compound inequality.

Solution Set: {p | p≤- 14 or p≥ 22}
Graph:

Practice makes perfect

We are asked to find and graph the solution set for all possible values of p in the given inequality. |2p-8/4|≥ 9 To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number greater than or equal to 9 away from the midpoint in the positive direction or in the negative direction. 2p-8/4≥ 9 or 2p-8/4≤ - 9Let's isolate p in both of these cases before graphing the solution set.

Case 1

2p-8/4≥9
2p-8 ≥ 36
2p ≥ 44
p ≥ 22

This inequality tells us that all values greater than or equal to 22 will satisfy the inequality.

Case 2

2p-8/4≤ - 9
2p-8 ≤ -36
2p ≤ -28
p ≤ -14

This inequality tells us that all values less than or equal to - 14 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the combination of the solution sets. First Solution Set:& p≥ 22 Second Solution Set:& p≤- 14 Combined Solution Set:& p≤ - 14 or p≥ 22

Graph

The graph of this inequality includes all values less than or equal to - 14 or greater than or equal to 22. We show this by keeping the endpoints closed.