c We can see in the Venn diagram that athletics and drama are not . Let's recall how to find the of two events, A and B, that are not mutually exclusive.
P(A or B)=P(A)+P(B)−P(A and B)
To find the probability of a student participating in athletics, we will divide the number of students in athletics that we found in Part B by the total students in the senior class that we found in Part A.
P(athletics)=345159
Let's find out how many students participate in drama by adding the number in every section of the drama circle in the Venn diagram.
Let's do it!
38+30+10+4=82
Now, to find the probability of a student participating in drama, we will divide the number of students in drama by the total amount of students.
P(drama)=34582
We will add the sections that both drama and athletics share in the diagram.
Let's do it!
4+10=14
To find the probability of a student participating in both athletics and drama, we will divide the students that participate in both activities by the total amount of students.
P(athletics and drama)=34514
Finally, we can find the probability of
P(athletics or drama).
P(athletics or drama)=P(athletics)+P(drama)−P(athletics and drama)
P(athletics or drama)=345159+34582−34514
P(athletics or drama)=345159+82−14
P(athletics or drama)=345227
We can write this probability as a .
P(athletics or drama)=345227
P(athletics or drama)=0.657971…
P(athletics or drama)≈0.66
P(athletics or drama)≈66%