To solve this problem, we first need to write the given information as . Let
x be the amount of adult tickets sold and
y be the amount of children's tickets sold. We are given that
925 tickets were sold. Let's write this as an equation.
x+y=925
We are also told that each adult ticket costs
$7.50 and that each children's ticket costs
$3.00. All the tickets were sold for
$5925. Let's write this as an equation.
7.5x+3y=5925
Combining these equations, we get a .
{x+y=9257.5x+3y=5925(I)(II)
To find out how many adult's ticket were sold, we need to solve this system for
x. To do that, we will use the Elimination Method to eliminate
y in one of the equations. Let's begin by multiplying Equation (I) by
-3.
{x+y=9257.5x+3y=5925(I)(II)
{-3(x+y)=-3(925)7.5x+3y=5925(I)(II)
{-3x−3y=-27757.5x+3y=5925(I)(II)
{-3x−3y=-27757.5x+3y+(-3x−3y)=5925+(-2775)(I)(II)
{-3x−3y=-27754.5x=3150(I)(II)
{-3x−3y=-2775x=700(I)(II)
We can see that
700 adult tickets were sold. Therefore, the correct answer is
F.