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McGraw Hill Glencoe Algebra 1, 2012

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McGraw Hill Glencoe Algebra 1, 2012 View details

8. Rational Equations

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Exercise 6 Page 730

Factor the denominators and multiply both sides of the equation by the least common denominator.

$x = - \frac{4}{3}$

Practice makes perfect

We will solve the given equation and then check the solutions.

Solving the Equation

We want to solve the given rational equation.

\frac{x + 3}{x ^{2} - 1} - \frac{2 x}{x - 1} = 1

We will start by factoring the denominators to find the least common denominator (LCD). Note that the second denominator is already factored. Let's factor the first one.

x^{2} - 1

Write as a power

x^{2} - 1^{2}

$a^{2} - b^{2} = (a + b) (a - b)$

(x + 1) (x - 1)

We can now rewrite the given expression.

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Subchapter links

Check Your Understanding p.730

H.O.T. Problems p.731

Standardized Test Practice p.732

Spiral Review p.732

Skills Review p.732