McGraw Hill Glencoe Algebra 1, 2012
MH
McGraw Hill Glencoe Algebra 1, 2012 View details
Preparing for Standardized Tests
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Exercise 1 Page 741

Start by finding the unit rate of puzzles per hour that can be completed by Hana and Eric, individually.

D

Practice makes perfect

We are told that Hana can finish a puzzle in 6 hours and Eric can do it in 5 hours. We will find the time t that it would take for them to do the job together. Let's start by finding the unit rate of puzzles per hour that can be completed by Hana and Eric, individually. Hana's Rate: & 1 puzzle/6hours [0.75em] Eric's Rate: & 1 puzzle/5 hours Note that the product of rate and time gives the fraction of the job done. We can multiply each rate by the time t to represent the amount of the job done by each person.

People Rate (puzzle/hour) Fraction of the Job Done
Hana 1/6 1/6 t
Eric 1/5 1/5 t

The sum of the fractions that represent the amount of the job done by each person will be equal to 1. 1/6 t+1/5 t= 1 We will solve this equation by multiplying both sides of the equation by the least common denominator (LCD).

1/6t+1/5t=1
30(1/6t+1/5t)=30
▼
Solve for t
30(1/6t)+30(1/5t)=30
30/6t+30/5t=30
5t+6t=30
11t=30
t=30/11
t=2.727272...
t≈ 2.7

It would take them about 2.7 hours to finish the puzzle together, which corresponds to option D.