Consider a triangle ABC with side lengths a, b, and c such that c2=a2+b2. The idea is to prove that m∠C=90∘.
Now, construct a right triangle
PQR such that
PR=b, QR=a, and
m∠R=90∘.
Write
PQ in terms of
a and
b by applying the .
PQ2=a2+b2
Remember that
c2=a2+b2. Then, set the left-hand sides of these equal to each other.
The last equation implies that the sides of
△ABC are to the sides of
△PQR.
abc=QR⇒ =PR⇒ =PQ⇒ BCACAB≅QR≅PR≅PQ
Triangles
ABC and
PQR are congruent by the . This implies that
∠C≅∠R, because are congruent. Remember, by construction
m∠R=90∘. Therefore,
m∠C=90∘ which completes the proof.