There are some aspects that are worth noting.
- The summation does not depend on the summation index used.
∑_(n=1)^4 2n = ∑_(k=1)^4 2k = ∑_(i=1)^4 2i = 20
- Sometimes a summation may involve other variables. These should not be confused with the summation index. ∑_(n=1)^3 2n/k
Here, the summation index is n. Therefore, the indicated values should only be substituted for n and not for k. ∑_(n= 1)^3 2n/k &= 2( 1)/k_(n= 1) + 2( 2)/k_(n= 2) + 2( 3)/k_(n= 3) [1.5em] ∑_(n=1)^3 2n/k &= 0.23cm2/k 0.23cm+ 0.23cm4/k 0.23cm+ 0.23cm6/k 0.23cm [1.5em] ∑_(n=1)^3 2n/k &= 12/k 3.35cm
- The initial value can be any integer less than or equal to the final index. The final index only indicates the last value to be substituted for n — it does not indicate the number of terms. ∑_(n= 8)^(10) 3n &= 3( 8)_(n= 8) + 3( 9)_(n= 9) + 3( 10)_(n= 10)
The summation notation is not only useful for working with sums involving a large number of terms, but it can also be used to represent an infinite sum. If an infinite number of terms is to be added, the symbol ∞
is used in the final index.
∑_(n=1)^(∞) 1/2^n=1/2^1+1/2^2+1/2^3+...