Houghton Mifflin Harcourt Algebra 1, 2015
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Houghton Mifflin Harcourt Algebra 1, 2015 View details
2. Using Intercepts
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Exercise 22 Page 178

Practice makes perfect
a We want to write and graph the equation that gives the balance f(x) in dollars of the abandoned checking account. Notice that the bank charges an $8 monthly fee for the account. Therefore, the $360 on the bank account decreases by $8 every month. Knowing this, we can write an equation f(x), where x represents the number of months.

f(x)= 360- 8xNext, we can use this linear equation to create a table of x- and f(x)-values. This way we will find the points lying on the graph of the equation. Notice that we can choose any positive x-values to find the points.

x f(x) = 360-8x f(x) Point
10 360-8( 10) 280 ( 10, 280)
20 360-8( 20) 200 ( 20, 200)
30 360-8( 30) 120 ( 30, 120)
40 360-8( 40) 40 ( 40, 40)

Finally, we can graph the equation by plotting the points and connecting them with a straight line.

b Now we want to find and interpret the x- and y-intercepts. Let's start with the x-intercept. To find it, we will substitute 0 for f(x) and we will solve the equation for x.

f(x)=360-8x
0=360-8x
8x=360
x=45

The x-intercept is 45. This means that, after 45 months, the money in the bank account will be $0. Now, we will find the y-intercept by substituting 0 for x and solving for f(x).

f(x)=360-8x
f( 0)=360-8( 0)
f(0)=360-0
f(0)=360

The y-intercept is 360. This means that the amount of money in the bank account started at $360.