Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 24 Page 409

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

- x + 2

Practice makes perfect
We want to find the following difference. 2(x+1)-3x First, let's distribute 2 into the first set of parentheses.
2(x+1)-3x
(2* x + 2 * 1) -3 x
(2x+2)-3x
Now, let's note that adding 0 to an expression does not change the value of the expression. For this reason, we can rewrite our expression as a difference of two linear expression. Let's do it! (2x+2)-3x = (2x+2)-(3x+ 0) Next, we will calculate this difference. First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(2x+2)-(3x+0)
(2x+2)+((-1) * 3x+(-1) * 0)
(2x+2)+(-3x+(-1) * 0)
(2x+2)+(-3x+0)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. ( 2x+ 2)+( -3x+ 0) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. 2 x +2& (+) -3 x +0& - x + 2& Therefore, we get the following result. (2x+2)-3x = - x + 2