Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 23 Page 409

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

-1 12x +1 12

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
( - 5/6x+5 12 )-( 2/3x+4)
( - 5/6x+5 12 )+( (-1) * 2/3x+ (-1) * 4)
( - 5/6x+5 12 )+( - 2/3x+ (-4))
( - 5/6x+5 12 )+( - 2/3x - 4)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. ( - 5/6x+ 5 12 )+( - 2/3x - 4) In this case, we have two x-terms and two constants. Let's add the terms.
( - 5/6x+5 12 )+( - 2/3x - 4)
- 5/6x - 2/3x+5 12 -4
â–Ľ
Simplify
- 5/6x - 2 * 2/3 * 2x+5 12 -4
- 5/6x - 4/6x+5 12 -4
-5/6x - 4/6x+5 12 -4
-5-4/6x +5 12 -4
-9/6x +1 12
-3/2x +1 12
â–Ľ
Write fraction as a mixed number
-2 -1/2x +1 12
(-2/2 - 1/2)x +1 12
(-1- 1/2)x +1 12
-1 12x +1 12