Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 19 Page 409

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

7x+5

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(4x+10)-(-3x + 5)
(4x+10)+((-1) * (-3x) + (-1) * 5)
(4x+10)+(3x + (-1) * 5)
(4x+10)+(3x + (-5))
(4x+10)+(3x -5)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined.

( 4x+ 10)+( 3x - 5) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. & 4 x +10 &+ 3 x-5 & 7 x +5 Therefore, we get the following result. (4x+10)-(-3x + 5)= 7x+5