Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 18 Page 409

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

-16x + 2

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(-8x+1)-(8x-1)
(-8x+1)+((-1) * 8x-(-1) * 1)
(-8x+1)+(-8x - (-1))
(-8x+1)+(-8x +1)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined.

( -8x+ 1)+( -8x + 1) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. -8 x +1& (+) -8 x +1& -16 x +2& Therefore, we get the following result. (-8x+1)-(8x-1) = -16x + 2