Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 17 Page 409

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

3x+13

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(9x+5)-(6x-8)
(9x+5)+((-1) * 6x-(-1) * 8)
(9x+5)+(-6x-(-8))
(9x+5)+(-6x + 8)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined.

( 9x+ 5)+( -6x + 8) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. 9 x +5 & (+) -6 x +8& 3 x +13& Therefore, we get the following result. (9x+5)-(6x-8) = 3x+13