Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 4 Page 407

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

4x+3

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(7x+5)-(3x+2)
(7x+5)+((-1) * 3x+ ( -1) * 2)
(7x+5)+(- 3x+ ( -2) )
(7x+5)+(- 3x -2 )
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined.

( 7x + 5)+( - 3x - 2 ) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. 7 x +5& (+) -3 x -2& 4 x +3& Therefore, we get the following result. (7x+5)-(3x+2) = 4x+3