Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Subtract Linear Expressions
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Exercise 2 Page 406

To find the additive inverse of a linear expression, you can multiply each term of the expression by -1.

- x + 10

Practice makes perfect
First, let's find the additive inverse of the linear expression within the second set of parentheses. To do so, we can distribute -1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by -1.
(6x+9)-(7x-1)
(6x+9)+(1-7x)
(- 7x+1)+(6x+9)
Now, let's identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. ( - 7x+ 1)+( 6x+ 9) In this case, we have two x-terms and two constants. Let's arrange the like terms in columns. Then, let's perform the addition. -7 x + 1 & + 6 x +9& - x +10& Therefore, we get the following result. (6x+9)-(7x-1) = - x + 10