First, let's find the of the within the second set of parentheses. To do so, we can
-1 into the second set of parentheses. When we do so, we multiply each term of that linear expression by
-1.
(2x+4)−(-x+5)
(2x+4)+(-1)(-x+5)
(2x+4)+(-1)(-x)+(-1)(5)
(2x+4)+x+(-1)(5)
(2x+4)+x−5
Now, let's identify which, if any, terms can be combined. Remember, only — or terms with the same — can be combined.
(2x+4)+x−5
In this case, we have two
x-terms and two
constants. Let's arrange the like terms in columns. Then, let's perform the addition.
22x+4+x−5223x−1
Therefore, we get the following result.
(2x+4)−(-x+5)=3x−1