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From the information in the exercise, we can identify three points though which the water from the green water hose passes.
Use the vertex form of a quadratic function.
The green hose
y=-4/25(x-5)^2+8
Domain: 0≤ x ≤ 10
Range: 4≤ y ≤ 8
We are given the information about Maura, who waters her outdoor plants. With the information we can identify a few data points that lie on the path of the water shooting from the green hose.
For the water shooting from the red hose we have been given its equation. Notice that it is written in vertex form. This allows us to identify its vertex ( h, k) immediately. y = a(x- h)^2 + k ⇕ y=-(x- 3)^2+ 7 The maximum height of the water from the red hose is 7 feet. Therefore, the water from the green hose throws water higher, as it reaches a maximum height of 8 feet.
To write an equation that models the path of the water from the green hose, we will consider the vertex form of a quadratic function.
y= a(x- h)^2+ k
In this form, ( h, k) is the vertex and a is the stretch factor of the parabola. From Part A, we know that the vertex is ( 5, 8). With this information, we can start writing the equation.
x= 0, y= 4
Subtract term
LHS-8=RHS-8
(- a)^2=a^2
.LHS /25.=.RHS /25.
Rearrange equation
Now we can finalize the equation in vertex form. y= a(x- 5)^2+ 8 ⇕ y= -4/25(x- 5)^2+ 8
The function goes from x=0 to x=10 including the endpoints. Therefore, its domain is all values greater than or equal to 0 but less than or equal to 10. We can write this as the following compound inequality. 0≤ x ≤ 10
The function goes from y=4 to y=8 including the endpoints. Therefore, its range is all values greater than or equal to 4 but less than or equal to 8. We can write this as the following compound inequality. 4≤ y ≤ 8