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Core Connections Integrated I, 2013

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Core Connections Integrated I, 2013 View details

2. Section 5.2

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Exercise 53 Page 265

Write the equation in slope-intercept form.

$y = - 10 x + 170$

Practice makes perfect

Let's draw the slope triangle between the known points.

The slope of a line is the vertical difference

Δ y

divided by the horizontal difference

Δ x .

From the slope triangle we see that these are

- 20

and

2,

respectively.

m = \frac{Δ y}{Δ x} \Leftrightarrow m = \frac{- 2 0}{2} = - 10

When we know the slope we can use the slope-intercept form to write the following equation.

y = - 10 x + b

To complete the equation we have to find the

y -

intercept also. We can do that by substituting one of the known points in the equation and solving for

b .

y = - 10 x + b

$x = 2$ , $y = 150$

150 = - 10 (2) + b

▼

Solve for

b

Multiply

150 = - 20 + b

$LHS + 20 = RHS + 20$

170 = b

Rearrange equation

b = 170

Now we can complete the equation of our line.

y = - 10 x + 170

Subchapter links

5.2.1 Generating and Investigating Sequences p.264-265

5.2.2 Generalizing Arithmetic Sequences p.269-270

5.2.3 Recursive Sequences p.273-274