2. Section 9.2
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V=π (1.5)^2(7)≈49.48 cm^3 The cylinder-shaped hole has a diameter of 1 cm, which means its radius is 0.5 cm. With this information, we can calculate the volume of the hole in the middle. V=π (0.5)^2(7)≈ 5.50 cm^3 Finally, we subtract the volume of the hole from the volume of the big cylinder including the hole. 49.48 - 5.50 = 43.98 cm^3
To calculate its area we can draw diagonals between opposite vertices, creating 8 congruent isosceles triangles. If we obtain the area of one triangle we can find the area of the base by multiplying this value by 8.
Substitute values
a/1=a
Rearrange equation
Use a calculator
Round to 2 decimal place(s)