Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
3. Section 2.3
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Exercise 106 Page 129

Practice makes perfect
a From the previous exercise, we know that the lines are perpendicular. This means the lines form a right angle at their point of intersection.

Additionally, the three sides of the triangle have different lengths. Therefore, we can conclude that the triangle is a scalene right triangle.

b To find the area of a triangle, we need to determine its base and height. If we consider the hypotenuse as the triangle's base, then its height will be drawn from the vertex with the right angle and perpendicular to the hypotenuse. Since the base is horizontal, the height must be vertical. Therefore, we can identify both dimensions from the diagram.
When we know the triangle's height and base, we can find it's area by multiplying these dimensions and dividing by 2.
A=1/2bh
A=1/2( 10)( 4)
Evaluate right-hand side
A=1/2(40)
A=40/2
A=20
c A shape's perimeter is the sum of its sides. We already know the length of the hypotenuse. To determine the length of its legs, we will first label the vertices so we can refer to them.
The length of the unknown legs, can be calculated by using the Distance Formula.
d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)
d_(AB)=sqrt(( - 2-( - 4))^2+( 4- 0)^2)
Evaluate right-hand side
d_(AB)=sqrt((- 2+4)^2+(4-0)^2)
d_(AB)=sqrt(2^2+4^2)
d_(AB)=sqrt(4+16)
d_(AB)=sqrt(20)
We also have to calculate the length of BC.
d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)
d_(BC)=sqrt(( - 2- 6)^2+( 4- 0)^2)
Evaluate right-hand side
d_(BC)=sqrt((-8)^2+4^2)
d_(BC)=sqrt(8^2+4^2)
d_(BC)=sqrt(64+16)
d_(BC)=sqrt(80)
When we know the length of all sides, we can determine the perimeter 10+sqrt(20)+sqrt(80)≈ 23.42 units