body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Core Connections: Course 3

CC

Core Connections: Course 3 View details

Chapter Closure

Continue to next subchapter

Exercise 63 Page 211

To solve the given equation for y, we will use the properties of equality to apply inverse operations to the equation. Remember, only like terms can be combined.

2x+5y=10

LHS-2x=RHS-2x

2x+5y-2x=10-2x

Subtract terms

5y=10-2x

.LHS /5.=.RHS /5.

5y/5=10-2x/5

Simplify quotient

y=10-2x/5

Write as a difference of fractions

y=10/5-2x/5

Calculate quotient

y=2-2x/5

To solve the given equation for x, we will use the properties of equality to apply inverse operations on the equation. Remember, only like terms can be combined.

3(x+2)=y-6

.LHS /3.=.RHS /3.

3(x+2)/3=y-6/3

Simplify quotient

x+2=y-6/3

LHS-2=RHS-2

x+2-2=y-6/3-2

Subtract terms

x=y-6/3-2

Write as a difference of fractions

x=y/3-6/3-2

Calculate quotient

x=y/3-2-2

Subtract term

x=y/3-4

Subchapter links

Exercises