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Core Connections: Course 2 View details

2. Section 7.2

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Exercise 100 Page 422

Practice makes perfect

We want to find the missing value in the given pair of equivalent ratios. x/10=6/15 To solve the proportion, we will start by using the Cross Products Property.

x/10=6/15

CrossMult

Cross multiply

15(x)=10(6)

Multiply

15x=60

From here, we will continue solving for x by using the Properties of Equality.

15x=60

DivEqn

.LHS /15.=.RHS /15.

15x/15=60/15

▼

Simplify left-hand side

MovePartNumRight

a* b/c=a/c* b

15/15x=60/15

QuotOne

a/a=1

1x=60/15

IdPropMult

Identity Property of Multiplication

x=60/15

CalcQuot

Calculate quotient

x=4

Checking Our Answer

Let's Check!

Now we can check our answer by substituting it into the original equation.

x/10=6/15

Substitute

x= 4

4/10? =6/15

ReduceFrac

a/b=.a /2./.b /2.

2/5? =6/15

ReduceFrac

a/b=.a /3./.b /3.

3/5=3/5

Because both sides of the equation are the same, we know that our solution is correct!

We want to find the missing value in the given pair of equivalent ratios. 12/9=8/x To solve the proportion, we will start by using the Cross Products Property.

12/9=8/x

CrossMult

Cross multiply

x(12)=9(8)

Multiply

12x=72

From here, we will continue solving for x by using the Properties of Equality.

12x=72

DivEqn

.LHS /12.=.RHS /12.

12x/12=72/12

▼

Simplify left-hand side

MovePartNumRight

a* b/c=a/c* b

12/12x=72/12

QuotOne

a/a=1

1x=72/12

IdPropMult

Identity Property of Multiplication

x=72/12

CalcQuot

Calculate quotient

x=6

Checking Our Answer

Let's Check!

Now we can check our answer by substituting it into the original equation.

12/9=8/x

Substitute

x= 6

12/9? =8/6

ReduceFrac

a/b=.a /3./.b /3.

4/3? =8/6

ReduceFrac

a/b=.a /2./.b /2.

4/3=4/3

Because both sides of the equation are the same, we know that our solution is correct!

We want to find the missing value in the given pair of equivalent ratios. 16/38=200/m To solve the proportion, we will start by using the Cross Products Property.

16/38=200/m

CrossMult

Cross multiply

m(16)=38(200)

Multiply

16m=7600

From here, we will continue solving for m by using the Properties of Equality.

16m=7600

DivEqn

.LHS /16.=.RHS /16.

16x/16=7600/16

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