Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 8.2
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Exercise 108 Page 406

Graph each inequality separately.

Practice makes perfect

We will graph each inequality separately. Then we will combine the graphs. Let's start!

Inequality I

To determine the boundary line of the first inequality, we need to exchange the inequality symbol for an equals sign. Inequality:& y ≥ |x+2|-3 Boundary Line:& y = |x+2|-3 The graph of this boundary line is the graph of the parent function y=|x| translated left 2 units and down 3 units. The boundary line will be solid because the inequality is non-strict.

Next, we need to decide which side of the boundary line we should shade. We can do this by testing a point that does not lie on the boundary line. If the point satisfies the inequality, it lies in the solution set. If not, we will shade the other region. Let's use (0,0).

y≥ |x+2|-3
0? ≥| 0+2|-3
â–¼
Evaluate right-hand side
0? ≥|2|-3
0? ≥2-3
0≥ -1 ✓

Because (0,0) created a true statement, we will shade the region that contains this point.

Inequality II

Now that we have completed the first inequality, let's determine the boundary line of the second inequality. We will follow the same process once more. Inequality:& y ≤ 2 Boundary Line:& y=2 This boundary line is a horizontal line. The inequality y ≤ 2 describes all values of y that are less than or equal to 2. This means that every coordinate pair with an y-value that is less than or equal to 2 needs to be included in the shaded region. Notice that the inequality is non-strict, so the boundary line will be solid.

Combining the Inequality Graphs

In drawing the inequality graphs on the same coordinate plane, we are able to see the overlapping section.

We can now view only the solution set by removing the shaded regions that are not overlapping.