Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 10.2
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Exercise 88 Page 529

Practice makes perfect
a

The difference between a sequence and a series is that a sequence a_n is an ordered list of numbers, while a series S_n is the sequence of cumulative sums of those numbers.

In our case, the sequence corresponds to the list of the class sizes of the graduating classes in a particular year. The corresponding series represents the total number of graduating students in each year.

b

The given sequence is an arithmetic sequence.

t(n)=42+12(n-1) Therefore, to calculate the total number of graduates after the 10th graduation, we can use the following formula for the sum of an arithmetic series. S_n=n(t_1+t_n)/2 To use this formula we need to know the first and last term of the series. We can find the first term by substituting n=1 into the formula.

t(n)=42+12(n-1)
t( 1)=42+12( 1-1)
â–¼
Evaluate right-hand side
t(1)=42+12(0)
t(1)=42

Now we can find the last term by substituting n=10 in the formula.

t(n)=42+12(n-1)
t( 10)=42+12( 10-1)
â–¼
Evaluate right-hand side
t(10)=42+12(9)
t(10)=42+108
t(10)=150

After the 10th graduation ceremony there were t_(10)=150 graduates and that after the 1st ceremony there were t_1 =42 graduates. Now we can determine how many total graduates there should be.

S_(10)=10(t_1+t_(10))/2
S_(10)=10( 42+ 150)/2
â–¼
Evaluate right-hand side
S_(10)=10(192)/2
S_(10)=5(192)
S_(10)=960

c

The number of graduates after n years is represented by the following formula.

t(n)=42+12(n-1) Let's use the same formula as in Part B. If we substitute the equation above into this formula, we get a general equation for the number of invitations they have to make.

S_n=n(t_1+t_n)/2
S_n=n(42+(42+12(n-1)))/2
â–¼
Evaluate right-hand side
S_n=n(42+(42+12n-12))/2
S_n=n(42+42+12n-12)/2
S_n=n(72+12n)/2
S_n=72n+12n^2/2
S_n=2(36n+6n^2)/2
S_n=36n+6n^2