Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 10.1
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Exercise 36 Page 510

Since order does not matter, we are looking for the number of combinations.

15 teams

Practice makes perfect

We have a set of 6 people and must choose 4 of them. Since the order in which the players are chosen does not matter, we want to calculate the number of combinations. To do that, we can use the following formula. _nC_r=_nP_r/r! ⇔ _nC_r=n!/(n-r)!r! We have six players to choose from and want to create a group of four. Therefore, we have n= 6 and r= 4.

_nC_r=n!/(n-r)!r!
_6C_4=6!/( 6- 4)! 4!
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Evaluate right-hand side
_6C_4 = 6!/2!4!

Write as a product

_6C_4 = 6*5*4!/2!*4!
_6C_4 = 6*5*4!/2!*4!
_6C_4 = 6*5/2!

2!=2

_6C_4 = 6*5/2
_6C_4 = 30/2
_6C_4 = 15

There are 15 ways we can pick the team if order does not matter.

Alternative Solution

Using a Graphing Calculator
To calculate the number of combinations we can also use the built in combinations formula on our graphing calculator. We start by entering the number of players, which is 6.

Next, push the MATH button, scroll to PRB and choose the third option. Having chosen nCr, we finish by entering the number of people on the team, which is 4.

Note that we obtained exactly the same result as when calculating by using the formula for the number of combinations.