Exercise 53 Page 214

a We will use the Elimination Method to solve this system of equations. It is usually the best choice when one of the variables has equal or opposite coefficients, as they are in the given equation.

b When one of the variables is already isolated or has a coefficient of

1

- 1,

the Substitution Method seems to be the best choice. First, let's isolate

y

in the second equation.

{6 x = 7 - 2 y 4 x + y = 4 (I) (II)

SubEqn

$(II):$ $LHS - 4 x = RHS - 4 x$

{6 x = 7 - 2 y y = 4 - 4 x

Now we can substitute

4 - 4 x

for

y

in the first equation to find

x .

Subchapter links

5.2.1 Generating and Investigating Sequences p.213-215

5.2.2 Generalizing Arithmetic Sequences p.219

5.2.3 Recursive Sequences p.222