Big Ideas Math Geometry, 2014
BI
Big Ideas Math Geometry, 2014 View details
Quiz
Continue to next subchapter

Exercise 6 Page 328

Consider the Incenter Theorem.

NS=11

Practice makes perfect

We are told that N is the incenter of the triangle. This means that it is the point of concurrency of the angle bisectors.

According to the Incenter Theorem, the incenter of a triangle is equidistant from its sides. Therefore, NQ, NR, and NS have equal lengths. NQ=NR=NS Since we are given the expression for the lengths of NQ and NR, we can equate them to solve for x.

NQ=NR
2x+1= 4x-9
â–¼
Solve for x
1=2x-9
10=2x
5=x
x=5

Finally, we can calculate the lengths of any of the segments by substituting the value of x into either of the given expressions. NQ: 2( 5)+1 =11 NR: 4( 5)-9 =11 Because both of these segments have a length of 11, we know NS does as well.