Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
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Exercise 1 Page 328

15, see solution.

Practice makes perfect

Examining the given diagram, we can see that VW is perpendicular to SU. Moreover, since SW and WU have the same length, we know that the line intersects the segment at its midpoint. This means that VW is a perpendicular bisector of SU.

According to the Perpendicular Bisector Theorem, if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. In our case, since V lies on VW, we know it is equidistant from S and U. Therefore, SV and UV have equal lengths. SV=UV This allows us to equate the given expressions for their lengths to solve for x.

SV=UV
2x+11= 8x-1
â–¼
Solve for x
11=6x-1
12=6x
2=x
x=2

We found that x=2. Now we can find the length UV by substituting this value to the expression. UV: 8( 2)-1 =15