To find the , we can use the .
M(2x1+x2,2y1+y2)
Then we can use the midpoint to write the equation of the .
Finding the Midpoint
The coordinates of the given endpoints are
P(0,2) and
Q(6,-2). Let's use these to find the coordinates of the midpoint.
M(2x1+x2,2y1+y2)
M(20+6,22+(-2))
M(3,0)
The midpoint of
PQ is at
M(3,0). Let's see what this looks like on a .
Finding the Perpendicular Line
To find the line that runs perpendicular to
PQ, we first need to find the slope of the segment. We can do this by substituting
P(0,2) and
Q(6,-2) into the .
m=x2−x1y2−y1
m=6−0-2−2
m=-32
have opposite slopes. With this information, we know that
all lines that are perpendicular to our given line will have a slope of
23.
y=23x+b
By substituting the midpoint
M(3,0) into this equation for
x and
y, we can solve for the
y-intercept
b of the perpendicular line.
Now that we have the
y-intercept, we can complete the equation.
y=23x+(-29)⇔y=23x−29
Let's graph the line.