To find the , we can use the .
M(2x1+x2,2y1+y2)
Then we can use the midpoint to write the equation of the .
Finding the Midpoint
The coordinates of the given endpoints are
P(-5,-5) and
Q(3,3). Let's use these to find the coordinates of the segment's midpoint.
M(2x1+x2,2y1+y2)
M(2-5+3,2-5+3)
M(-1,-1)
The midpoint of
PQ is at
M(-1,-1). Let's see what this looks like on a .
Finding the Perpendicular Line
To find the line that runs perpendicular to
PQ, we first need to find the slope of the segment. We can do this by substituting
P(-5,-5) and
Q(3,3) into the .
m=x2−x1y2−y1
m=3−(-5)3−(-5)
m=1
have opposite slopes. With this information, we know that
all lines that are perpendicular to our given line will have a slope of
-1.
y=-1x+b⇔y=-x+b
By substituting the midpoint
M(-1,-1) into this equation for
x and
y, we can solve for the
y-intercept
b of the perpendicular line.
Now that we have the
y-intercept, we can complete the equation.
y=-x+(-2)⇔y=-x−2
Let's graph the line.