Exercise 8 Page 119

To solve the equation, we have to isolate x on one side using inverse operations. To begin with, we want to collect all of the constants on one side of the equation. The inverse operation to subtraction is addition, so to eliminate 26 we have to subtract 26 from both sides of the equation. Next, we have to eliminate 2 from in front of the parenthetical factor. Since multiplication and division are inverse operations, we have to divide by 2.

2(3x+11)=- 44

DivEqn

.LHS /2.=.RHS /2.

2(3x+11)/2=- 44/2

CalcQuot

Calculate quotient

3x+11=- 22

Once more, we have to eliminate the constant from the left-hand side of the equation. To do it, let's subtract 11 from both sides of the equation.

3x+11=- 22

SubEqn

LHS-11=RHS-11

3x+11 - 11=- 22 - 11

SubTerms

Subtract terms

3x=- 33

Finally, we have to eliminate 3 from in front of x. Again, we have to divide both sides of the equation.

3x=- 33

DivEqn

.LHS /3.=.RHS /3.

3x/3=- 33/3

CalcQuot

Calculate quotient

x=- 11