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Choose an arbitrary value for b between 0 and 1. Then, draw the graphs of an exponential decay function y=bx and the scatter plot.
See solution.
Since we have an exponential decay function, the value of b must be greater than 0 and less than 1. For simplicity, let's consider b=0.5. The graph of y=0.5x decreases as x increases, and passes through the points (0,1) and (1,0.5). Also, its horizontal asymptote is the line y=0.
We will make a table of values for the first five points of the scatter plot. Let's use the same value, b=0.5.
Point | Substitute | Simplify |
---|---|---|
(1,b1) | (1,0.51) | (1,0.5) |
(2,b1+b2) | (2,0.51+0.52) | (2,0.75) |
(3,b1+b2+b3) | (3,0.51+0.52+0.53) | (3,0.875) |
(4,b1+b2+b3+b4) | (4,0.51+0.52+0.53+0.54) | (4,0.9375) |
(5,b1+b2+b3+b4+b5) | (5,0.51+0.52+0.53+0.54+0.55) | (5,0.96875) |
Now, let's plot these points.
We see that the graph contains the point (1,0.5). The graph is increasing. Moreover, it appears that the line y=1 is a horizontal asymptote.
We can also consider the differences between the graphs.