Exercise 16 Page 162

To calculate h( - 13) we need to substitute - 13 for x in each instance of the x-variable.

h(x)=5x^3-3x^2+2x+4

Substitute

x= - 1/3

h( - 1/3)=5( - 1/3)^3-3( - 1/3)^2+2( - 1/3)+4

CalcPow

Calculate power

h(- 1/3)=5(- 1/27)-3(1/9)+2(- 1/3)+4

MoveLeftFacToNumOne

a* 1/b= a/b

h(- 1/3)=- 5/27-3/9-2/3+4

CalcQuot

Calculate quotient

h(- 1/3)=- 5/27-1/3-2/3+4

AddSubTerms

Add and subtract terms

h(- 1/3)=2 2227