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Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
1. Graphing Polynomial Functions
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Exercise 15 Page 162

We need to substitute 12 for x in each instance of the x-variable.

p(1/2)=11 14

Practice makes perfect
To calculate p( 12) we need to substitute 12 for x in each instance of the x-variable.
p(x)=2x^3+4x^2+6x+7
Substitute

x= 1/2

p( 1/2)=2( 1/2)^3+4( 1/2)^2+6( 1/2)+7
CalcPow

Calculate power

p(1/2)=2(1/8)+4(1/4)+6(1/2)+7
MoveLeftFacToNumOne

a* 1/b= a/b

p(1/2)=2/8+4/4+6/2+7
CalcQuot

Calculate quotient

p(1/2)=1/4+1+3+7
AddTerms

Add terms

p(1/2)=11 14
Subchapter links expand_more
arrow_right Communicate Your Answer p.157
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arrow_right Monitoring Progress p.158-161
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Monitoring Progress 5 (Page 159)
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Monitoring Progress 10 (Page 161)
Monitoring Progress 11 (Page 161)
arrow_right Exercises p.162-164
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Exercises 11 (Page 162)
Exercises 12 (Page 162)
Exercises 13 (Page 162)
Exercises 14 (Page 162)
Exercises 15 (Page 162)
Exercises 16 (Page 162)
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Exercises 37 (Page 163)
Exercises 38 (Page 163)
Exercises 39 (Page 163)
Exercises 40 (Page 163)
Exercises 41 (Page 163)
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Exercises 45 (Page 164)
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Exercises 47 (Page 164)
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Exercises 51 (Page 164)
Exercises 52 (Page 164)
Exercises 53 (Page 164)
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