First, determine the quadrant in which the point lies.
Function f could include (-2, 3) when a=3/4.
Practice makes perfect
The point (- 2,3) should be in the second quadrant, since the x-coordinate of the point is negative and the y-coordinate of it is positive. Hence, the function f(x) could include the point.
Let's substitute the point into the function f(x)=ax^2.
