Exercise 1 Page 286

We will determine the equation that has the given graph.

We can see that the y-intercept of the line is y=-9. Therefore, we can begin by writing an equation in slope-intercept form, y=mx+b, where m is the slope and b is the y-intercept. y=mx -9 Now we will find the slope by substituting (2,0) in the above equation.

y=mx-9

SubstituteII

x= 2, y= 0

0=m( 2)-9

AddEqn

LHS+9=RHS+9

9=m(2)

DivEqn

.LHS /2.=.RHS /2.

9/2=m

RearrangeEqn

Rearrange equation

m=9/2

We found that the slope is 92. Now we can complete the equation. y= 9/2x -9 Next, since the given equation is in standard form we will rewrite the equation in standard form as well.

y=9/2x-9

MultEqn

LHS * 2=RHS* 2

2y=9x-18

SubEqn

LHS--9x=RHS--9x

-9x+2y=-18

Therefore, the equation of the line is given in option D.