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The form of an exponential function modeling compound interest is y= P(1+ rn)^(nt).
Example functions: y_1= 1000(1.12)^t and y_2= 1000(1.01)^(12t)
Better option: y_2= 1000(1.01)^(12t)
Explanation: See solution.
Let's recall the form of an exponential function modeling compound interest.
y= P(1+ r/n)^(nt)
| Account 1 | Account 2 |
|---|---|
| Annual interest rate 12 %, compounded annually | Annual interest rate 12 %, compounded monthly |
| Initial amount $1000 | |
| y_1= 1000(1+ 0.12/1)^(1* t) [1.5em] ⇕ [0.7em] y_1= 1000(1.12)^t | y_2= 1000(1+ 0.12/12)^(12* t) [1.5em] ⇕ [0.7em] y_2= 1000(1.01)^(12t) |
Note that both accounts offer the same annual interest rate. Then, which is the best option? Well, there is a big difference. Notice that Account 2 composes the interest monthly, while Account 1 does this once a year. We can see the impact of this effect in the graph below.
As we can see, the amount in Account 2 eventually overcomes the amount in Account 1. This is because the interest is compounded each month, and then the next month generates interest over a quantity already possessing an interest benefit. This is why that account's money grows faster, and therefore, is the best option.