Sign In
| Student Learning Objectives: |
|---|
|
| | 12 Theory slides |
| | 12 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
On a sunny Saturday morning, Kevin — a boy with a passion for formula 1 racing cars — wakes up and finds a letter sitting on the table. It is from his pops.
The first task Kevin faces is to get to his uncle's bakery without the help of his phone's GPS. He is given two things: a tape measure and a map with a marked route.
Most maps include the math of a particular relation between two units of measure. One of the measures refers to distances on the map itself and the other refers to actual distances. This relationship is called a scale. Other real-life tools use this relationship as well.
The scale of a model or drawing is the ratio between any length on the model or drawing and its corresponding length on the actual object or place.
lLength on the drawing : lCorresponding length on the actual object
Suppose a drawing has a scale of 1 in:100 ft. This means that 1 inch on the drawing represents 100 feet on the actual object. Apart from the colon notation, a scale can be expressed using an equals sign or as a fraction, as it is a ratio.
| Denoting a Scale | |
|---|---|
| Ratio | 1 in : 100 ft |
| Equals Sign | 1 in = 100 ft |
| Fraction | 1 in/100 ft |
When a scale is written without specifying the units, it is understood that both numbers have the same unit of measure. For example, a scale of 1:2 means that the actual object is twice the size of the model. A scale of 1:0.5 means that the actual object is half the size of the model — whether it be in meters, inches, yards, and so on.
A scale drawing is a two-dimensional drawing that is similar to an actual object or place. In a scale drawing, the ratio of any length on the drawing to the actual length is always the same and equal to the scale of the drawing. drawing→/actual→ l_1/L_1 = l_2/L_2 ←drawing/←actual Possible examples of scale drawing are floor plans, blueprints, and maps.

On Kevin's map, the scale is 1.5in=90yd. This means that 1.5 inches on the map represents 90 yards in real life. On the map, Kevin's route is 15.65 inches long. Let l be the actual distance. The following equation can be set. 1.5in/90yd = 15.65in/l By solving this equation for l, the distance Kevin walked from his house to his uncle's bakery can be found.
After correctly determining the distance traveled to the bakery, Kevin's uncle trades him the tape measure for a smartwatch and a new map. Kevin's next task is to reach his aunt's house. There is one catch — his route has to pass through the local bank.
| Place 1 | Place 2 | Distance on the Map (in) | Actual Distance (mi) |
|---|---|---|---|
| Bakery | Bank | 2.85 | 0.75 |
| Bank | Aunt's house | x | 0.70 |
Since a map is a scale drawing, the ratio of any length on the drawing to the actual length always remains the same. Based on that, the following equation is created. drawing→/actual→ 2.85/0.75 = x/0.70 ←drawing/←actual The value of x can be found by solving this equation.
LHS * 0.70=RHS* 0.70
Calculate quotient
Multiply
Rearrange equation
On the map, the bank and the aunt's house are 2.66 inches apart.
If the original real-life situation involves a three-dimensional object, making a scale model is more useful than a drawing. The idea behind a scale model is the same as a scale drawing, but the model has three dimensions instead of two.
A scale model is a three-dimensional model that is similar to a three-dimensional object. The ratio of a linear measurement of a model to the corresponding linear measurement of the actual object is always the same and equal to the scale of the model. model→/actual→ l_1/L_1 = l_2/L_2 ←model/←actual Here is an example scale model of a building.

The lighthouse door is closed and the code to open it is the actual height of the lighthouse, measured in meters. For a moment, Kevin does not know what to do. He realizes that he should open the backpack his aunt gave him. Inside, he finds a scale model of the lighthouse and a tape measure.
Kevin figures it out and manages to measure the width of the base of the lighthouse. Also, he measures the width and height of the scale model with the tape measure.
| Scale Model | Lighthouse | |
|---|---|---|
| Width | 10cm | 5.25m |
| Height | 30cm | ? |
Determine the code that opens the lighthouse door.
Cross multiply
Multiply
.LHS /10.=.RHS /10.
Calculate quotient
The height of the lighthouse is 15.75 meters. Kevin is ready to enter the lighthouse.
The length scale factor of a scale drawing or scale model is the ratio of a length on the drawing or model to the corresponding actual length where both lengths have the same units of measure.
Length scale factor = Length on model/Actual length
At the top of the lighthouse, Kevin finds a blueprint of his room and a scale model of his house shed. He understands that he must return home.
Kevin uses the tape measure and finds that his bed is 1.80 meters long. He then goes to the backyard and measures the width of the shed. It is 4.50 meters wide. What is the pin of the padlock?
| Blueprint Dimensions (cm) | Actual Dimensions (m) | |
|---|---|---|
| Bed length | 9 | 1.80 |
| Bed width | 5 |
Before finding the length scale factor, all the dimensions should be written with the same units of measure. Use the fact that 1 meter is the same as 100 centimeters to convert 1.80 meters to centimeters. 1.80m* 100cm/1m = 180cm Next, divide the bed length on the blueprint by the actual length of the bed to find the scale factor.
The length scale factor of the blueprint is 120. This means that the actual dimensions of the bed — and the entire room — were divided by 20 to make the blueprint.
Similarly, the length scale factor of the scale shed can be found. The width and length of the model are known and Kevin measured the actual width of the shed.
| Scale Model Dimensions (cm) | Actual Dimensions (m) | |
|---|---|---|
| Length | 20 | |
| Width | 15 | 4.50 |
As before, write all the dimensions using the same units of measure. 4.50m * 100cm/1m = 450cm The length scale factor is the quotient between the width of the scale shed and the actual width of the shed.
Now that both length scale factors are known, the pin of the padlock can be found. Recall, it is 156 times the sum of the length scale factors.
Substitute values
a/b=a * 30/b * 30
a/b=a * 20/b * 20
Multiply
Add fractions
a/b=.a /50./.b /50.
a* 1/b= a/b
Calculate quotient
The pin to open the padlock is 13.
Kevin eagerly opens the chest. He discovers a tablet! Upon powering it on, a map with a marker at his current position and another marker at his next stop appear. Kevin then presses the navigate button. Oh no! The app locks and asks him what the actual distance is between the marked places, in yards.
Substitute values
LHS * x=RHS* x
.LHS /0.0004.=.RHS /0.0004.
Calculate quotient
Rearrange equation
The places are 22 500 inches apart. This can be converted to yards by using the fact that 36 inches are the same as 1 yard. 22 500in* 1yd/36in = 625yd The actual distance between the marked places is 625 yards. This means that the pin that unlocks the app is 625. Enter it to see the route and follow Kevin's adventure.
When Kevin arrived at the last destination, his father was there waiting with a huge smile and a box in his hands. Inside, there was a scale formula 1 racing car made with a length scale factor of 116!
Kevin can get the scale car as a prize for his adventure if he can find the exact length, in centimeters, of the model without using any measuring tool. His father tells him that the actual formula 1 car is about 5.6 meters long. What is the length of the model?
Length Scale factor= 1/16
LHS * 560=RHS* 560
1/b* a = a/b
Calculate quotient
Rearrange equation
The length of the scale formula 1 is 35 centimeters.
The length scale factor gives the relationship between the dimensions of a scale drawing and the original drawing. Kevin wonders whether the areas are also related somehow. Use the following applet to investigate it.
| Area of Original Triangle | Length Scale Factor | Area of Scale Triangle | Ratio of Areas |
|---|---|---|---|
| 2.8 | 2 | 11.2 | 11.2/2.8 = 4 = 2^2 |
| 2.8 | 0.5= 1/2 | 0.7 | 0.7/2.8 = 0.25 = 1/4 = ( 1/2)^2 |
| 2.8 | 1.5= 3/2 | 6.3 | 6.3/2.8 = 2.25 = 9/4 = ( 3/2)^2 |
A distance of 40 kilometers on a map is represented by a 3-centimeter line.
If the map is enlarged to 4 times its size, what will be the scale of the enlarged map? Write it as a fraction in its simplest form.
We want to find the scale of the enlarged map. First, recall that the scale is the ratio of a length on the scale drawing to the corresponding actual length. Scale = Length on drawing/Actual length We know that on the map a distance of 40 kilometers is represented by a 3-centimeter line. Since the map is enlarged to 4 times its size, a 3-centimeter line becomes a 4* 3=12-centimeter line. However, notice that we enlarged the distances on the map, but the actual distances stay the same. Initial Map &= 3cm Enlarged Map &= 12cm Actual Distance &= 40km Therefore, on the enlarged map, 40 kilometers are represented by a 12-centimeter line. This indicates the scale of the new map.
The scale of the enlarged map is 3cm:10km or 3cm10km.