11. Scale Drawings
Sign In
An error ocurred, try again later!
Chapter 9
11.
Scale Drawings
| Student Learning Objectives: |
|---|
|
Why
Scale drawings are used to represent objects that are too large or too small to be drawn to their actual size. They maintain proportions through a scale factor, showing the relationship between the real size and the drawn size. This lesson covers how to work with scale, including calculating the length scale factor and using it in drawings and models to create accurate representations.
Lesson Settings & Tools
| | 12 Theory slides |
| | 12 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Scale Drawings
Slide of 12
It is sometimes utterly impossible to accurately model an object or real-life scenario using the original dimensions. Here, scale drawings and models come into action. This lesson will expand on how these tools are instrumental in modeling some common cases.
Catch-Up and Review
Here are a few recommended readings before getting started with this lesson.
Share
Report error
Translate
Challenge
Maps and Actual Distances
On a sunny Saturday morning, Kevin — a boy with a passion for formula 1 racing cars — wakes up and finds a letter sitting on the table. It is from his pops.
The first task Kevin faces is to get to his uncle's bakery without the help of his phone's GPS. He is given two things: a tape measure and a map with a marked route.
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":"yd","answer":{"text":["939"]}}
Share
Report error
Translate
Discussion
The Scale of a Map
Most maps include the math of a particular relation between two units of measure. One of the measures refers to distances on the map itself and the other refers to actual distances. This relationship is called a scale. Other real-life tools use this relationship as well.
Concept
Scale
The scale of a model or drawing is the ratio between any length on the model or drawing and its corresponding length on the actual object or place.
lLength on the drawing : lCorresponding length on the actual object
Suppose a drawing has a scale of 1 in:100 ft. This means that 1 inch on the drawing represents 100 feet on the actual object. Apart from the colon notation, a scale can be expressed using an equals sign or as a fraction, as it is a ratio.
| Denoting a Scale | |
|---|---|
| Ratio | 1 in : 100 ft |
| Equals Sign | 1 in = 100 ft |
| Fraction | 1 in/100 ft |
When a scale is written without specifying the units, it is understood that both numbers have the same unit of measure. For example, a scale of 1:2 means that the actual object is twice the size of the model. A scale of 1:0.5 means that the actual object is half the size of the model — whether it be in meters, inches, yards, and so on.
External credits: Derek Quinn
Share
Report error
Translate
Discussion
Scale Drawing
A scale drawing is a two-dimensional drawing that is similar to an actual object or place. In a scale drawing, the ratio of any length on the drawing to the actual length is always the same and equal to the scale of the drawing. drawing→/actual→ l_1/L_1 = l_2/L_2 ←drawing/←actual Possible examples of scale drawing are floor plans, blueprints, and maps.
On Kevin's map, the scale is 1.5in=90yd. This means that 1.5 inches on the map represents 90 yards in real life. On the map, Kevin's route is 15.65 inches long. Let l be the actual distance. The following equation can be set. 1.5in/90yd = 15.65in/l By solving this equation for l, the distance Kevin walked from his house to his uncle's bakery can be found.
1.5in/90yd = 15.65in/l
l = 939 yd
Share
Report error
Translate
Example
Finding a Missing Length
After correctly determining the distance traveled to the bakery, Kevin's uncle trades him the tape measure for a smartwatch and a new map. Kevin's next task is to reach his aunt's house. There is one catch — his route has to pass through the local bank.
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":"inches","answer":{"text":["2.66"]}}
Hint
A map is a scale drawing. Then, the ratio of any length on the drawing to the actual length is always the same. The watch shows the distances traveled, where the first distance indicates the distance between the bakery and the bank.
Solution
Kevin's smartwatch gives the actual distances between the visited places. According to the map, the bakery and the bank are 2.85 inches apart. Let x be the distance between the bank and the aunt's house on the map.
| Place 1 | Place 2 | Distance on the Map (in) | Actual Distance (mi) |
|---|---|---|---|
| Bakery | Bank | 2.85 | 0.75 |
| Bank | Aunt's house | x | 0.70 |
Since a map is a scale drawing, the ratio of any length on the drawing to the actual length always remains the same. Based on that, the following equation is created. drawing→/actual→ 2.85/0.75 = x/0.70 ←drawing/←actual The value of x can be found by solving this equation.
2.85/0.75 = x/0.70
▼
Solve for x
MultEqn
LHS * 0.70=RHS* 0.70
2.85/0.75* 0.70 = x
CalcQuot
Calculate quotient
3.8* 0.70 = x
Multiply
Multiply
2.66 = x
RearrangeEqn
Rearrange equation
x = 2.66
On the map, the bank and the aunt's house are 2.66 inches apart.
Share
Report error
Translate
Discussion
Scale for Three Dimensional Objects
If the original real-life situation involves a three-dimensional object, making a scale model is more useful than a drawing. The idea behind a scale model is the same as a scale drawing, but the model has three dimensions instead of two.
Concept
Scale Model
A scale model is a three-dimensional model that is similar to a three-dimensional object. The ratio of a linear measurement of a model to the corresponding linear measurement of the actual object is always the same and equal to the scale of the model. model→/actual→ l_1/L_1 = l_2/L_2 ←model/←actual Here is an example scale model of a building.
Share
Report error
Translate
Example
Height of a Lighthouse
The lighthouse door is closed and the code to open it is the actual height of the lighthouse, measured in meters. For a moment, Kevin does not know what to do. He realizes that he should open the backpack his aunt gave him. Inside, he finds a scale model of the lighthouse and a tape measure.
External credits: Ekayasa.Design
Kevin figures it out and manages to measure the width of the base of the lighthouse. Also, he measures the width and height of the scale model with the tape measure.
| Scale Model | Lighthouse | |
|---|---|---|
| Width | 10cm | 5.25m |
| Height | 30cm | ? |
Determine the code that opens the lighthouse door.
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":"Code:","formTextAfter":null,"answer":{"text":["15.75"]}}
Hint
In a scale model, the ratio of a linear measurement on the model to the corresponding linear measurement on the actual object is always the same.
Solution
Let x be the height of the lighthouse. In a scale model, the ratio of a linear measurement on the model to the corresponding linear measurement on the actual object is always the same. This leads to writing the following equation.
model→/actual→ 10cm/5.25m = 30cm/x ←model/←actual
The height of the lighthouse can be found by solving the previous equation for x.
10/5.25 = 30/x
CrossMult
Cross multiply
10x = 5.25* 30
Multiply
Multiply
10x = 157.5
DivEqn
.LHS /10.=.RHS /10.
x = 157.5/10
CalcQuot
Calculate quotient
x = 15.75
The height of the lighthouse is 15.75 meters. Kevin is ready to enter the lighthouse.
Share
Report error
Translate
Discussion
Length Scale Factor
The length scale factor of a scale drawing or scale model is the ratio of a length on the drawing or model to the corresponding actual length where both lengths have the same units of measure.
Length scale factor = Length on model/Actual length
Share
Report error
Translate
Example
Finding Length Scale Factors
At the top of the lighthouse, Kevin finds a blueprint of his room and a scale model of his house shed. He understands that he must return home.
External credits: juicy_fish
Kevin uses the tape measure and finds that his bed is 1.80 meters long. He then goes to the backyard and measures the width of the shed. It is 4.50 meters wide. What is the pin of the padlock?
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":"Pin:","formTextAfter":null,"answer":{"text":["13"]}}
Hint
Be sure all the dimensions are written with the same units of measure before finding the length scale factor.
Solution
The length scale factor of the blueprint is the ratio of a dimension on the blueprint to the corresponding actual dimension. The dimensions of the bed on the blueprint are written on its side. Additionally, Kevin measured his actual bed length.
| Blueprint Dimensions (cm) | Actual Dimensions (m) | |
|---|---|---|
| Bed length | 9 | 1.80 |
| Bed width | 5 |
Before finding the length scale factor, all the dimensions should be written with the same units of measure. Use the fact that 1 meter is the same as 100 centimeters to convert 1.80 meters to centimeters. 1.80m* 100cm/1m = 180cm Next, divide the bed length on the blueprint by the actual length of the bed to find the scale factor.
The length scale factor of the blueprint is 120. This means that the actual dimensions of the bed — and the entire room — were divided by 20 to make the blueprint.
Similarly, the length scale factor of the scale shed can be found. The width and length of the model are known and Kevin measured the actual width of the shed.
| Scale Model Dimensions (cm) | Actual Dimensions (m) | |
|---|---|---|
| Length | 20 | |
| Width | 15 | 4.50 |
As before, write all the dimensions using the same units of measure. 4.50m * 100cm/1m = 450cm The length scale factor is the quotient between the width of the scale shed and the actual width of the shed.
Now that both length scale factors are known, the pin of the padlock can be found. Recall, it is 156 times the sum of the length scale factors.
Pin = 156 (scale factor1 + scale factor2 )
SubstituteValues
Substitute values
Pin = 156 ( 1/20+ 1/30)
▼
Simplify
ExpandFrac
a/b=a * 30/b * 30
Pin = 156 (1* 30/20* 30 + 1/30 )
ExpandFrac
a/b=a * 20/b * 20
Pin = 156 (1* 30/20* 30 + 1* 20/30* 20 )
Multiply
Multiply
Pin = 156 (30/600 + 20/600 )
AddFrac
Add fractions
Pin = 156 * 50/600
ReduceFrac
a/b=.a /50./.b /50.
Pin = 156 * 1/12
MoveLeftFacToNumOne
a* 1/b= a/b
Pin = 156/12
CalcQuot
Calculate quotient
Pin = 13
The pin to open the padlock is 13.
Share
Report error
Translate
Example
Next Stop
Kevin eagerly opens the chest. He discovers a tablet! Upon powering it on, a map with a marker at his current position and another marker at his next stop appear. Kevin then presses the navigate button. Oh no! The app locks and asks him what the actual distance is between the marked places, in yards.
External credits: Freepik
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":null,"answer":{"text":["625"]}}
Hint
The ratio of the distance on the tablet to the actual distance is equal to the length scale factor. Use the fact that 36 inches are the same as 1 yard.
Solution
Since a map is a scale drawing, the ratio of any length on the map to the actual length is always the same and equal to the length scale factor.
Length in map/Corresponding actual length = k
This means that the ratio of the distance between the marked places on the tablet to the actual distance is equal to the length scale factor. Let x be the actual distance. According to the information given by the app, the places are 9 inches apart on the screen and the scale factor is 0.0004.
Length in map/Actual length = k
SubstituteValues
Substitute values
9in/x = 0.0004
▼
Solve for x
MultEqn
LHS * x=RHS* x
9in = 0.0004* x
DivEqn
.LHS /0.0004.=.RHS /0.0004.
9in/0.0004 = x
CalcQuot
Calculate quotient
22 500in = x
RearrangeEqn
Rearrange equation
x = 22 500in
The places are 22 500 inches apart. This can be converted to yards by using the fact that 36 inches are the same as 1 yard. 22 500in* 1yd/36in = 625yd The actual distance between the marked places is 625 yards. This means that the pin that unlocks the app is 625. Enter it to see the route and follow Kevin's adventure.
Share
Report error
Translate
Example
Length in a Scale Model
When Kevin arrived at the last destination, his father was there waiting with a huge smile and a box in his hands. Inside, there was a scale formula 1 racing car made with a length scale factor of 116!
External credits: kjpargeter
Kevin can get the scale car as a prize for his adventure if he can find the exact length, in centimeters, of the model without using any measuring tool. His father tells him that the actual formula 1 car is about 5.6 meters long. What is the length of the model?
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":"cm","answer":{"text":["35"]}}
Solution
Let x be the length of the scale car, in centimeters. Since the length of the actual car is given in meters, convert it to centimeters first.
5.6m* 100cm/1m = 560cm
The actual formula 1 car is 560 centimeters long. The ratio of the length of the scale car to the length of the actual car is equal to the length scale factor, 116.
Length Scale factor = x/560
Substitute
Length Scale factor= 1/16
1/16 = x/560
▼
Solve for x
MultEqn
LHS * 560=RHS* 560
1/16* 560 = x
MoveRightFacToNumOne
1/b* a = a/b
560/16 = x
CalcQuot
Calculate quotient
35 = x
RearrangeEqn
Rearrange equation
x = 35
The length of the scale formula 1 is 35 centimeters.
Share
Report error
Translate
Closure
Relating the Area of a Scale Drawing to the Actual Area
The length scale factor gives the relationship between the dimensions of a scale drawing and the original drawing. Kevin wonders whether the areas are also related somehow. Use the following applet to investigate it.
| Area of Original Triangle | Length Scale Factor | Area of Scale Triangle | Ratio of Areas |
|---|---|---|---|
| 2.8 | 2 | 11.2 | 11.2/2.8 = 4 = 2^2 |
| 2.8 | 0.5= 1/2 | 0.7 | 0.7/2.8 = 0.25 = 1/4 = ( 1/2)^2 |
| 2.8 | 1.5= 3/2 | 6.3 | 6.3/2.8 = 2.25 = 9/4 = ( 3/2)^2 |
Share
Report error
Translate
Scale Drawings
Exercise 2.1
The blueprint for a floor of an industrial building is shown where 12 inch represents 3 feet on the actual building.
What is the actual area of the conference room?
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":"A=","formTextAfter":"ft^2","answer":{"text":["302.4"]}}
security
report
code
security
report
code
We need to determine the actual dimensions of the conference room. Let l be its length and w be its width. Since a blueprint is a scale drawing, the ratio of any length on the blueprint to the actual length is always the same and equal to the scale of the blueprint. blueprint→/actual→ l_1/L_1 = Scale The scale of the blueprint is 12in=3ft. On the blueprint, the conference room is 3.50 inches long. Let's use this information to find the actual length of the conference room.
The actual length of the conference room is 21 feet. Similarly, let's find the actual width. On the blueprint, the conference room is 2.40 inches wide.
The actual width of the conference room is 14.4 feet. We are ready to find the actual area of the conference room. Since it is a rectangle, the area is the product of the length and width. A = 14.4* 21 ⇒ A = 302.4 The actual conference room has an area of 302.4 square feet.
security
report
code
E
Hint & Answer
S
Solution
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":null,"answer":{"text":["1\/8","\\dfrac{1}{8}"]}}
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":"A=","formTextAfter":"ft^2","answer":{"text":["120"]}}
security
report
code
security
report
code
We know that the length scale factor of a scale drawing is the ratio of a dimension on the drawing to the corresponding actual dimension. Length scale factor = Length on drawing/Actual length Ramsha used a scale of 3in:2ft which means that 3 inches on the drawing represents 2 feet on the actual room. Since the dimensions have different units of measure, let's first convert feet to inches. 2ft * 12in/1ft = 24in Now that we have all the dimensions in inches, we are ready to find the length scale factor.
The length scale factor of the drawing is 18.
The area of the actual room is the product of the length and width, which we do not know. Then, let's begin by defining a pair of variables representing the actual dimensions of the room.
l &= actual length w &= actual width
We know that the ratio of a dimension on the drawing to the actual dimension is equal to the length scale factor. From the previous part, we know that the length scale factor is 18. We also know that the drawing is 18 inches long and 15 inches wide.
| Length | Width | |
|---|---|---|
| Ratio | 18in/l = 1/8 | 15in/w = 1/8 |
| Cross Multiply | 8* 18in = l* 1 | 8* 15in = w* 1 |
| Multiply | 144in = l | 120in = w |
The actual room is 144 inches long and 120 inches wide. Let's convert these dimensions to feet by using the fact that 12 inches are the same as 1 foot. 144in * 1ft/12in &= 12ft [0.75em] 120in * 1ft/12in &= 10ft Ramsha's room is 12 feet long and 10 feet wide. We can find its area by multiplying its dimensions. A = 12ft* 10ft ⇓ A = 120ft^2
security
report
code
E
Hint & Answer
S
Solution
Kevin replicated a character he saw in a cartoon book onto a poster. On the poster, he drew the character 0.75 meters tall.
If Kevin used a length scale factor of 2.5, what is the height of the character in the cartoon book?
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":"cm","answer":{"text":["30"]}}
security
report
code
security
report
code
We begin by recalling that the length scale factor is the ratio of a length on the model to the corresponding actual length where both lengths have the same units of measure. Length scale factor = Length on drawing/Actual length Let x be the height of the character on the cartoon book, in meters. We know that on the drawing Kevin made, the character is 0.75 meters tall. Also, we know the length scale factor is 2.5. This information will help us find the value of x.
In the cartoon book, the character is 0.3 meters tall. Since we are asked to answer in centimeters, let's convert the height by using the fact that 1 meter is the same as 100 centimeters. 0.3m* 100cm/1m = 30cm The character is 30 centimeters tall on the cartoon book.
security
report
code
E
Hint & Answer
S
Solution
In computer class, Emily drew a rectangular circuit board for a small TV remote. She used a length scale factor of 5. If the actual length of the circuit board is 60 millimeters, what is the length of the circuit board Emily drew in centimeters?
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":""},"formTextBefore":null,"formTextAfter":"cm","answer":{"text":["30"]}}
security
report
code
security
report
code
We begin by recalling that the length scale factor is the ratio of a length on the model to the corresponding actual length where both lengths have the same units of measure. Length scale factor = Length on drawing/Actual length Let l be the length of the circuit board on Emily's drawing. We know that the actual circuit board is 60 millimeters long. Also, we know the length scale factor is 5. Let's use this information to find the value of l.
In the drawing, the circuit board is 300 millimeters long. Since we are asked to answer in centimeters, let's convert the length by using the fact that 1 centimeter is the same as 10 millimeters. 300mm* 1cm/10mm = 30cm Emily drew a rectangular circuit board that is 30 centimeters long.
security
report
code
E
Hint & Answer
S
Solution
Scale Drawings
Recommended exercises
To get personalized recommended exercises, please login first.
Loading content
Edit Lesson
≥
>
■2
■▢
e▢
7
8
9
×
÷■1
=
=
√▢
▢√
∫▢▢
4
5
6
+
−
≤
<
log
ln
log▢
1
2
3
()
∣
sin
cos
tan
0
.
π
x
y
Loading content