Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
2. Reflections
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Exercise 6 Page 557

Use the line through P that is perpendicular to the line of reflection.

R_(y-axis)(P(x,y))= P'(- x,y)
R_(x-axis)(P(x,y))= P'(x,- y)

Practice makes perfect

We will first write an equation for the coordinates of the point P(x,y) reflected across the y-axis.

Reflection Across the y-axis

Let's find the coordinates of the point P(x,y) reflected across the y-axis. R_(y-axis)(P(x,y)) = ? We will draw a diagram to find the location of the reflected point P'. To do so, we will move along the line through P that is perpendicular to the line of reflection. Then, we stop when the distances of P and P' to the line of reflection are the same.

We see that the point P'(- x,y) is the image of P(x,y). Therefore, we can write the equation for the coordinates of the point P(x,y) reflected across the y-axis as follows. R_(y-axis)(P(x,y)) = P'(- x,y)

Reflection Across the x-axis

We will now find the coordinates of a point P(x,y) reflected across the x-axis. R_(x-axis)(P(x,y)) = ? Let's draw a diagram to find the location of the reflected point. To do so, we will move along the line through P that is perpendicular to the line of reflection and then stop when the distances of P and P' to the line of reflection are the same.

We see that the point P'(x,- y) is the image of P(x,y). Therefore, we can write the equation for the coordinates of the point P(x,y) reflected across the x-axis as follows. R_(x-axis)(P(x,y)) = P'(x,- y)