Sign In
Recall the classification of quadrilaterals. You can begin by finding the slopes of the sides.
Name: Square
Area: 20 units squared
Let's plot the given points on a coordinate plane and graph the quadrilateral.
First, we will determine the most precise name for our quadrilateral. Then we can find its area.
To determine the most precise name for our quadrilateral, let's review the classification of quadrilaterals.
| Quadrilateral | Definition |
|---|---|
| Parallelogram | Both pairs of opposite sides are parallel |
| Rhombus | Parallelogram with four congruent sides |
| Rectangle | Parallelogram with four right angles |
| Square | Parallelogram with four congruent sides and four right angles |
| Trapezoid | Quadrilateral with exactly one pair of parallel sides |
| Isosceles Trapezoid | Trapezoid with legs that are congruent |
| Kite | Quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent |
Now, let's find the slopes of the sides using the Slope Formula.
| Side | Points | y_2-y_1/x_2-x_1 | Simplify |
|---|---|---|---|
| JK | J( 1,-3), K( 3,1) | 1-( -3)/3- 1 | 2 |
| KL | K( 3,1), L( 7, -1) | -1- 1/7- 3 | - 1/2 |
| LM | L( 7, -1), M( 5, -5) | -5-( -1)/5- 7 | 2 |
| MJ | M( 5, -5), J( 1,-3) | -3-( -5)/1- 5 | - 1/2 |
We can tell that the slopes of the opposite sides of our quadrilateral are equal. Therefore, both pairs of opposite sides are parallel and the quadrilateral is a parallelogram. We can also tell that the consecutive sides are perpendicular, as their slopes are opposite reciprocals. 2 ( - 1/2 ) = -1 Therefore, our quadrilateral is either a rectangle or a square. To check, we can find the lengths of its sides using the Distance Formula.
| Side | Points | sqrt((x_2-x_1)^2+(y_2-y_1)^2) | Simplify |
|---|---|---|---|
| JK | J( 1,-3), K( 3,1) | sqrt(( 3- 1)^2+( 1-( -3))^2) | sqrt(20) |
| KL | K( 3,1), L( 7, -1) | sqrt(( 7- 3)^2+( -1- 1)^2) | sqrt(20) |
| LM | L( 7, -1), M( 5, -5) | sqrt(( 5- 7)^2+( -5-( -1))^2) | sqrt(20) |
| MJ | M( 5, -5), J( 1,-3) | sqrt(( 1- 5)^2+( -3-( -5))^2) | sqrt(20) |
Our parallelogram has four congruent sides. Therefore, the most precise name for this quadrilateral is a square.
To find the area, we can use the formula for the area of a square. A=s^2 In this case s= sqrt(20). Let's substitute it in the formula to find A. A= ( sqrt(20))^2 ⇔ A=20 The area of our square is 20 units squared.