Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
7. Polygons in the Coordinate Plane
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Exercise 34 Page 404

Recall the classification of quadrilaterals. You can begin by finding the slopes of the sides.

Name: Square
Area: 20 units squared

Practice makes perfect

Let's plot the given points on a coordinate plane and graph the quadrilateral.

First, we will determine the most precise name for our quadrilateral. Then we can find its area.

Name

To determine the most precise name for our quadrilateral, let's review the classification of quadrilaterals.
Quadrilateral Definition
Parallelogram Both pairs of opposite sides are parallel
Rhombus Parallelogram with four congruent sides
Rectangle Parallelogram with four right angles
Square Parallelogram with four congruent sides and four right angles
Trapezoid Quadrilateral with exactly one pair of parallel sides
Isosceles Trapezoid Trapezoid with legs that are congruent
Kite Quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent

Now, let's find the slopes of the sides using the Slope Formula.

Side Points y_2-y_1/x_2-x_1 Simplify
JK J( 1,-3), K( 3,1) 1-( -3)/3- 1 2
KL K( 3,1), L( 7, -1) -1- 1/7- 3 - 1/2
LM L( 7, -1), M( 5, -5) -5-( -1)/5- 7 2
MJ M( 5, -5), J( 1,-3) -3-( -5)/1- 5 - 1/2

We can tell that the slopes of the opposite sides of our quadrilateral are equal. Therefore, both pairs of opposite sides are parallel and the quadrilateral is a parallelogram. We can also tell that the consecutive sides are perpendicular, as their slopes are opposite reciprocals. 2 ( - 1/2 ) = -1 Therefore, our quadrilateral is either a rectangle or a square. To check, we can find the lengths of its sides using the Distance Formula.

Side Points sqrt((x_2-x_1)^2+(y_2-y_1)^2) Simplify
JK J( 1,-3), K( 3,1) sqrt(( 3- 1)^2+( 1-( -3))^2) sqrt(20)
KL K( 3,1), L( 7, -1) sqrt(( 7- 3)^2+( -1- 1)^2) sqrt(20)
LM L( 7, -1), M( 5, -5) sqrt(( 5- 7)^2+( -5-( -1))^2) sqrt(20)
MJ M( 5, -5), J( 1,-3) sqrt(( 1- 5)^2+( -3-( -5))^2) sqrt(20)

Our parallelogram has four congruent sides. Therefore, the most precise name for this quadrilateral is a square.

Area

To find the area, we can use the formula for the area of a square. A=s^2 In this case s= sqrt(20). Let's substitute it in the formula to find A. A= ( sqrt(20))^2 ⇔ A=20 The area of our square is 20 units squared.