Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
4. Volumes of Prisms and Cylinders
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Exercise 22 Page 722

Look for three numbers such that their product equals 80. Could you think of another set of numbers?

Example prisms: 2 cm by 5 cm by 8 cm and 2 cm by 4 cm by 10 cm.

Practice makes perfect

Let's begin by writing the formulas to find the volume and the surface area of a rectangular prism. Here, we can be specific since the area of the base is width times length.

We are asked for two prisms with a volume of 80 cm^3 each. Therefore, one possible set of dimensions that works is w=2 cm, l =5 cm, and h=8 cm.

Let's find the surface area of this first prism.

SA_1 = 2(w* l + w* h + l * h)
SA_1 = 2( 2* 5 + 2* 8 + 5 * 8)
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Simplify right-hand side
SA_1 = 2(10 + 16 + 40)
SA_1 = 2(66)
SA_1 = 132

The surface area of the first prism is 132 cm^2. Since we want the two prisms to have different surface areas, the dimensions of the second prism must be different from those of the first prism. A second set of dimensions that works is w=2 cm, l =4 cm, and h=10 cm.

We've seen that the second prism has a volume of 80 cm^3. Let's find its surface area.

SA_2 = 2(w* l + w* h + l * h)
SA_2 = 2( 2* 4 + 2* 10 + 4 * 10)
â–¼
Simplify right-hand side
SA_2 = 2(8 + 20 + 40)
SA_2 = 2(68)
SA_2 = 136

As we can see, the surface area of the second prism is different from the surface area of the first one.

Solid Width (cm) Length (cm) Height (cm) Volume (cm^3) Surface Area (cm^2)
Prism 1 2 5 8 80 132
Prism 2 2 4 10 80 136

Keep in mind that there are other dimensions that satisfy the required conditions, so your answer may vary.