Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 1 Page 607

Does the difference between any two consecutive terms always have the same value?

Recursive Rule: a_n=a_(n-1)+6, a_1=7
Explicit Rule: a_n=7+6(n-1), for n≥ 1
a_(12):73

Practice makes perfect

We want write the recursive rule and the explicit rule for the given sequence. Let's pay close attention to the difference between consecutive terms. 7 + 6 âź¶ 13 + 6 âź¶ 19+ 6 âź¶ 25 + 6 âź¶ 31 + 6 âź¶ ... We can see that the difference between consecutive terms is 6. Therefore, the given sequence is an arithmetic sequence.

Recursive Rule

Let's now consider the general formula for a recursive rule.

a_1& =a a_n&=a_(n-1)+d,forn≥ 2 In the above formula, a is the first term of the sequence and d is the common difference. For our sequence, the first term is 7 and the common difference is 6. a_1& = 7 a_n&=a_(n-1)+ 6,forn≥ 2

Explicit Rule

Finally, let's recall the general formula of the explicit rule for an arithmetic sequence. a_n=a_1+d(n-1) Here, a_1 represents the first term of the sequence and d is the common difference. As we have already stated, for our sequence, we have a= 7 and d= 6. a_n= 7+ 6(n-1)

Finding the 12th Term

To find the value of the 12th term, we substitute n= 12 into this equation and evaluate the right-hand side.
a_n=7+6(n-1)
a_(12)=7+6( 12-1)
a_(12)=7+6(11)
a_(12)=7+66
a_(12)=73
The 12th term in the sequence is 73.